"The resistor is used to reduce the current to the coil not to reduce the
voltage." What bullshit. Ohm's Law says E=IR. So if you increase R
(resistance) you get a voltage drop. The resistor reduces the voltage
across the coil, and this reduces the series current through both the coil
and the points. You'ld fail as an electrical engineer in my town. Six
volt cars did not need or use ballast resistors. The coils were wound to
draw the correct point current at six volts. It's when you switch your
production to twelve volt cars in 1956 that you can save some money if you
can use up the six volt coil production from 1955 and before using a
dropping resistor.
Richard
At 10:04 PM -0400 8/20/98, Larry C. Stanley wrote:
>Jim,
>
>The resistor is used to reduce the current to the coil not to reduce the
>voltage. This helps the points to last longer. 12 volt cars use a 12 volt
>coil, 6 volt cars use a 6 volt coil. The 1955 to 1958 parts book shows the
>number for a 12 volt system resistor but only shows a package of coil and
>resistor for the Imperial (1818 840). I will have to check, but I think the
>resistance is different from 6 volt to 12 volt. Mopar did not use a coil
>with an internal resistor in the 50's. If you do not use a resistor, you
>will get a hotter spark ( good temporary cure for a weak coil ) but you
>will burn up the points quickly. On 1957 and earlier Plymouths, the
>resistor is mounted on the coil bracket. On the 1958 Plymouth, the resistor
>is under the master cylinder on the mounting plate.
>
>Will check on the resistance differences.
>
>Larry Stanley peerless@xxxxxxxxxxx
>
>----------
>> From: JAMES T. BENNETT <jbennett@xxxxxxxxxxxx>
>> To: L-FORWARDLOOK@xxxxxxxxxxxxx
>> Subject: [FWDLK] Ballast Resister 1955 vs. 1956 Imperial
>> Date: Tuesday, August 18, 1998 9:18 AM
>>
>> Is the ballast resister the same for the 1955 Imperial (6-volt system) as
>> it is for the 1956 Imperial (12-volt system)?
>>
>> Thanks for any help that you can provide.
>>
>> Jim
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