Ed - Sure is! The book says that for the front, slot the spring thru the hole in the 'web' on one end and the spring LINK on the other. For the rears, slot thru the spring LINK on one end and the spring LOOP on the other. I'm gonna try it that way for now. Can anyone add to this ? Ron ----- Original Message ----- From: <eddee@xxxxxxxxxxxxx> To: "Ron Waters" <ronbo97@xxxxxxxxxxx> Sent: Friday, August 05, 2005 1:18 PM Subject: Re: [FWDLK] Four Coils vs. Five Coils > Hi Ron > > This is convoluted > > There are 4 and 5 coil,,,but you have 2 places to install the springs!! > > All the new (newer I should say) replacement springs are the 5 coil and state that no matter how they were installed stock,,,install them ,front and rear,,on the INSIDE shoe hole (not on the exterior hole) > > I think the orig intent was to have the fronts grip a fraction of a second before the rears. We are lucky if they work at all--- > > ED > > ----- Original Message ----- > From: Ron Waters <ronbo97@xxxxxxxxxxx> > Date: Friday, August 5, 2005 10:40 am > Subject: [FWDLK] Four Coils vs. Five Coils > > > Hi Mopar Brake Lovers - > > > > Just finishing the installation of the brakes on my 58 Plymouth. > > The book > > mentions four-coil springs on the front and five-coil springs on > > the rear, > > which is what was on the brake assemblies when I disassembled them to > > install the new shoes. The new springs I ordered from Andy > > Bernbaum were all > > the same and a smaller size than the originals. Will this make a > > differencein the performance of the brakes and if so, where can I > > get the correct > > four-coil and five-coil springs ? > > > > Thanks ! > > > > Ron > > > > ************************************************************* > > > > To unsubscribe or set your subscription options, please go to > > http://lists.psu.edu/cgi-bin/wa?SUBED1=l-forwardlook&A=1 > > ************************************************************* To unsubscribe or set your subscription options, please go to http://lists.psu.edu/cgi-bin/wa?SUBED1=l-forwardlook&A=1
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