Re: [Chrysler300] HP as a function of RPM, torque

["Steve Galezowski" <stevenlulu@xxxx>]

As a point of interest, note that given the formula for HP, torque and HP
are always equal at 5252 RPM!

Steve Galezowski

----- Original Message -----
From: "Warren R Anderson" <wranderson@xxxx>
To: <JOEBRIL@xxxx>; <Chrysler300@xxxxxxxxxxxxxxx>; <dan300f@xxxx>
Sent: Thursday, November 14, 2002 7:28 PM
Subject: [Chrysler300] HP as a function of RPM, torque


>
>
> >I am unfamiliar with how peak horsepower is calculated or whether it has
> >anything to do with peak torque
>
> An engine on a dynamometer, rotational horsepower is calculated from
torque
> and RPM numbers. Torque can be measured and RPM can be measured;
horsepower
> is a calculated number. HP = Torque x RPM / 5252(units conversion factor
> where Torque is in lbs-ft).
>
> An internal combustion engine is not a constant or linear torque or a
> constant or linear HP machine. Horsepower available (calculated from
torque
> and RPM) will be a variable and will reach a maximum (peak) at some RPM.
> Measured torque will likewise reach some maximum peak but at some other
RPM.
> They will not peak at the same RPM.
>
> Given dyno torque and RPM numbers, peak torque at some RPM can be
> determined. From calculated HP figures, peak HP is determined. Computers
do
> all this of course as you see on TV when the Horsepower TV guys run a car
on
> their DynoJet (sp ?) inertia chassis dyno.
>
> Etc., etc. HTH
>
> Warren Anderson
> Sedona.AZ
>
>
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